The last character must be 0 for the answer to be possibly true. Yet, when we traverse the array from left to right, the encoding length must be 2 if the new traversed element is `1`

, (either `10`

or `11`

) and 1 if the new traversed element is `0`

```
class Solution {
public boolean isOneBitCharacter(int[] bits) {
int len = bits.length;
int i=0;
while(i<len){
if(i == len-1 && bits[len-1] == 0){
return true;
}
if(bits[i] == 1){
i += 2;
}else if(bits[i] == 0){
i++;
}
}
return false;
}
}
```