# Python easy to understand 45ms

• ``````class Solution(object):
"""
:type a: str
:type b: str
:rtype: str
"""

rem = 0

if len(a) >= len(b):
larg, short = a, b
else:
larg, short = b, a

# Going from the back of the strings to the front, checking with if statements to perform the simple math

for x in range(0,len(larg)):
if x < len(short):
if short[len(short)-x-1] == "1" and larg[len(larg)-x-1] == "1":
if rem == 1:
larg = larg[:len(larg)-x-1] + "1" + larg[len(larg)-x-1+1:]
else:
larg = larg[:len(larg)-x-1] + "0" + larg[len(larg)-x-1+1:]
rem = 1
else:
if short[len(short)-x-1] == "1" or larg[len(larg)-x-1] == "1":
if rem == 1:
larg = larg[:len(larg)-x-1] + "0" + larg[len(larg)-x-1+1:]
rem = 1
else:
larg = larg[:len(larg)-x-1] + "1" + larg[len(larg)-x-1+1:]
rem = 0
elif rem == 1:
larg  = larg[:len(larg)-x-1] + "1" + larg[len(larg)-x-1+1:]
rem = 0
else:
if rem == 1:
if larg[len(larg)-x-1] == "1":
larg  = larg[:len(larg)-x-1] + "0" + larg[len(larg)-x-1+1:]
else:
larg  = larg[:len(larg)-x-1] + "1" + larg[len(larg)-x-1+1:]
rem = 0
else:
break

if rem == 1:
larg = "1" + larg

return larg
``````

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