# Python solution

• ``````
import heapq

class Solution(object):
def topKFrequent(self, words, k):
"""
:type words: List[str]
:type k: int
:rtype: List[str]
"""
max_heap_freq = list()
hashtable = dict()

# calculate the frequency of all the words
for word in words:
# hashtable[word] = hashtable.get(word, 0) + 1
if hashtable.get(word, None) is None:
hashtable[word] = 1
else:
hashtable[word] += 1
# insert all the (word, freq) into the max_heap by comparing with values
for word, freq in hashtable.items():
heapq.heappush(max_heap_freq, (-freq, word))

min_heap_word = [] # if the freq is same sort them by smallest alphabetical order
result = []
for ki in range(k):
if len(min_heap_word) > 0 and min_heap_word[0][1] != max_heap_freq[0][0]:
while len(min_heap_word) > 0:
result.append(heapq.heappop(min_heap_word)[0])
freq, word = heapq.heappop(max_heap_freq)
heapq.heappush(min_heap_word, (word, freq))
while len(min_heap_word) > 0:
result.append(heapq.heappop(min_heap_word)[0])
return result

``````

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