Swift O(n log n) solution with inline comments

  • 0

    Brief Swift implementation with step by step comments.

    class Solution {
        func merge(_ intervals: [Interval]) -> [Interval] {
            var result: [Interval] = []
            // sort the intervals by start so we can test for overlaps sequentially
            let intervalsSorted = intervals.sorted(by: {$0.start < $1.start})
            // iterate the intervals
            for interval in intervalsSorted {
                // does the current interval overlap the last
                if !result.isEmpty && interval.start <= result.last!.end {
                    // there is overlap, rewrite the last interval with the
                    // higher end value, the start value must be <= current
                    // due to the prior sort
                    result.last!.end = max(result.last!.end, interval.end)
                } else {
                    // no overlap (or no last), append current interval
            return result

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