# My simple java solution

• ``````public class Solution {
public String convert(String s, int nRows) {

if(nRows <=1)
return s;

StringBuilder[] r = new StringBuilder[nRows];
for( int i=0; i<nRows; i++ )
r[i] = new StringBuilder();

int base = nRows+nRows-2;
char[] toks = s.toCharArray();
for(int i = 0; i < toks.length; i++)
{
int t = i % base;
if(t < nRows)
{
r[t].append(toks[i]);
}
else
{
r[base-t].append(toks[i]);
}
}

for( int i = 1; i<nRows; i++ )
r[0].append( r[i] );
return r[0].toString();
}
}``````

• why when I input ABC , 2 expected output is ACB , I think the output should be ABC , who can tell me ? why?

I got it , thanks for nelson3's reply!

A
C
B
when you read each line, is ACB

• Just realize that the format if off....

You have 2 rows, so the zigzag pattern will be
A(0, 0) C(0, 1)
B(1, 0).
If you consider the zigzag format as in a matrix form, the digits in the parentheses show the row and column number of the characters in that matrix . Then if you read them line by line (row by row), the result will be ACB.

Another example is ABCDEFGHIJKL, 4. Now you have 4 rows, the zipzag format of the string will be
A(0,0) G (0,3)
B(1, 0) F(1,2) H (1, 3) L (1,5)
C(2,0) E(2,1) I (2, 3) K (2, 4)
D(3,0) J (3, 3)
and the line-by-line output will be AGBFHLCEIKDJ.

• I assume ABC in two rows representation should be:
A C
[second row] B

• I have the same question with yours. Could you tell me something about it? Why excepted is ACB and output is ACB is wrong.

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