C++ simple O(n) time O(1) space solution, no Backtracking or DFS

  • 0
        bool checkValidString(string s) {
            int star=0, l=0, r=0;
            for(int i=0;i<s.size();i++) {
                if(s[i]=='*') star++;
                else if(s[i]=='(') l++;
                else l--;
                if(l+star<0) return false;
            for(int i=s.size()-1;i>=0;i--) {
                if(s[i]=='*') star++;
                else if(s[i]==')') r++;
                else r--;
                if(r+star<0) return false;
            return true;

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