Dynamic programming explanation

  • 2
    class Solution {
        //Dynamic programming. Using OPT[i] refers to the max profit we can get from first i days.
        /*OPT[i] = OPT[i-1] do nothing in day i or buy ticket in day i.
          OPT[i] = price[i] - smallest_value_from_first_i-1_days.
        public int maxProfit(int[] prices) {
            //one exception: no day
            if(prices.length == 0)  return 0;
            int[] OPT = new int[prices.length];
            int smallest = prices[0];
            for(int i = 1; i < prices.length; i++){
                OPT[i] = Math.max(OPT[i-1], prices[i]-smallest);
                smallest = Math.min(smallest, prices[i]);
            return OPT[OPT.length-1];

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