JavaScript solution


  • 0
    S
    function hasPathSum(root, sum) {
        if(root == null){
    		return false;
        }
        if(root.left == null && root.right == null){
    	if(sum == root.val){
                return true;
            }else{
                return false;
            }
        }
        return hasPathSum(root.left, sum - root.val) || hasPathSum(root.right, sum - root.val);
    }

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