Python, Straightforward with Explanation

  • 0

    If we remove some edge from parent A to child B, then the subtree at B must have sum equal to the sum of all the nodes divided by 2.

    Let's remember the subtree sum of every child node (stored in sums) as we calculate the subtree sum of the root. After, we simply check that some subtree could equal half the total. We must also be careful that there is an edge to delete, hence the check for "not root.left and not root.right".

    def checkEqualTree(self, root):
        sums = set()
        def sum_(node, child = False):
            if not node: return 0
            ans = node.val + sum_(node.left, True) + sum_(node.right, True)
            if child: sums.add(ans)
            return ans
        total = sum_(root)
        if total % 2 or not root.left and not root.right:
            return False
        return total // 2 in sums

  • 0

    Fails for example [0,1,-1] (returns True). (Edit: not anymore)

  • 0

    @StefanPochmann Corrected it, thanks.

Log in to reply

Looks like your connection to LeetCode Discuss was lost, please wait while we try to reconnect.